There’s no place like home.

And the bigger the game in sports, the more that adage comes into play.

The Cavaliers are, of course, right in the middle of that. They will try to win the first NBA championship in their 46 years of existence when the visit the Golden State Warriors Sunday night at 8 in Game 7 of the league finals.

It won’t be easy.

The Warriors are outstanding.

And they are even more so when they’re at home, where they lose about as often as Hillary Clinton and Donald Trump exchange pleasantries.

But the Cavs are certainly capable of doing it — again. They won at Oakland in their last try there in Game 5.

We’ll see how it all works out.

This is new territory for the Cavs, as they have never made it to Game 7 of the Finals.

The Indians have been to Game 7 of the World Series once, and it was on the road as they lost to the Florida Marlins in 1997.

The Browns have played on the road in the league championship game five times, posting a 2-3 record.

They won the All-America Football Conference title in 1947 by defeating the New York Yankees 14-3 at Yankee Stadium.

In 1951, the Browns, in their second season in the NFL, lost a league championship game for the first time in their six years of existence, falling 24-17 to the Los Angeles Rams at the Coliseum.

Two years later, in 1953, they lost to the Detroit Lions in the title game for the second straight season, 17-16 at Briggs Stadium.

The Browns returned to the Coliseum in 1955 and crushed the Rams 38-14 to earn the NFL crown.

And finally, in 1957, the Browns were the ones getting crushed in the NFL Championship Game, 59-14 at Detroit.

So Cleveland teams are 2-4 all-time on the road in winner-take-all league championship game.

The Cavs need to do something about that.